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Add test for cast join on keys with second analyze

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vdimir 2021-03-05 17:58:46 +03:00
parent 4a8708fbb2
commit 3da3794c7e
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2 changed files with 6 additions and 0 deletions
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3
tests/queries/0_stateless/01721_join_implicit_cast_long.reference
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@ -182,6 +182,7 @@
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0 0 -10 0 990
@ -382,6 +383,7 @@
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@ -582,6 +584,7 @@
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3
tests/queries/0_stateless/01721_join_implicit_cast_long.sql
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@ -61,6 +61,7 @@ SELECT sum(b) = 103 FROM t1 LEFT JOIN t2 USING (a) WHERE b > 102 AND t2.b < 204;
SELECT sum(t2.b) = 203 FROM t1 RIGHT JOIN t2 USING (a) WHERE b > 102 AND t2.b < 204;
SELECT sum(a) == 2 + 3 + 4 FROM t1 FULL JOIN t2 ON (t1.a + t1.b = t2.a + t2.b - 100) WHERE t1.b < 105 AND t2.b > 201;
SELECT sum(a) == 55 FROM t1 FULL JOIN t2 ON (t1.a + t1.b = t2.a + t2.b - 100) WHERE 1;
SELECT a > 0, sum(a), sum(b) FROM t1 FULL JOIN t2 USING (a) GROUP BY (a > 0) ORDER BY a > 0;
SELECT a > 0, sum(a), sum(t2.a), sum(b), sum(t2.b) FROM t1 FULL JOIN t2 ON (t1.a == t2.a) GROUP BY (a > 0) ORDER BY a > 0;
@ -135,6 +136,7 @@ SELECT sum(b) = 103 FROM t1 LEFT JOIN t2 USING (a) WHERE b > 102 AND t2.b < 204;
SELECT sum(t2.b) = 203 FROM t1 RIGHT JOIN t2 USING (a) WHERE b > 102 AND t2.b < 204;
SELECT sum(a) == 2 + 3 + 4 FROM t1 FULL JOIN t2 ON (t1.a + t1.b = t2.a + t2.b - 100) WHERE t1.b < 105 AND t2.b > 201;
SELECT sum(a) == 55 FROM t1 FULL JOIN t2 ON (t1.a + t1.b = t2.a + t2.b - 100) WHERE 1;
SELECT a > 0, sum(a), sum(b) FROM t1 FULL JOIN t2 USING (a) GROUP BY (a > 0) ORDER BY a > 0;
SELECT a > 0, sum(a), sum(t2.a), sum(b), sum(t2.b) FROM t1 FULL JOIN t2 ON (t1.a == t2.a) GROUP BY (a > 0) ORDER BY a > 0;
@ -210,6 +212,7 @@ SELECT sum(b) = 103 FROM t1 LEFT JOIN t2 USING (a) WHERE b > 102 AND t2.b < 204;
SELECT sum(t2.b) = 203 FROM t1 RIGHT JOIN t2 USING (a) WHERE b > 102 AND t2.b < 204;
SELECT sum(a) == 2 + 3 + 4 FROM t1 FULL JOIN t2 ON (t1.a + t1.b = t2.a + t2.b - 100) WHERE t1.b < 105 AND t2.b > 201;
SELECT sum(a) == 55 FROM t1 FULL JOIN t2 ON (t1.a + t1.b = t2.a + t2.b - 100) WHERE 1;
SELECT a > 0, sum(a), sum(b) FROM t1 FULL JOIN t2 USING (a) GROUP BY (a > 0) ORDER BY a > 0;
SELECT a > 0, sum(a), sum(t2.a), sum(b), sum(t2.b) FROM t1 FULL JOIN t2 ON (t1.a == t2.a) GROUP BY (a > 0) ORDER BY a > 0;