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fix unbundled failure test
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@ -1,6 +1,6 @@
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SELECT count()\nFROM \n(\n SELECT \n a, \n runningDifference(a) AS rd\n FROM \n (\n SELECT a\n FROM \n (\n SELECT 1 AS a\n UNION ALL\n SELECT 2 AS a\n )\n ORDER BY a DESC\n )\n WHERE rd = -1\n)
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1
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SELECT \n k, \n v, \n d, \n i\nFROM \n(\n SELECT \n t.1 AS k, \n t.2 AS v, \n runningDifference(v) AS d, \n runningDifference(xxHash32(t.1)) AS i\n FROM \n (\n SELECT arrayJoin([(\'a\', 1), (\'a\', 2), (\'a\', 3), (\'b\', 11), (\'b\', 13), (\'b\', 15)]) AS t\n )\n)\nWHERE i = 0
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SELECT \n k, \n v, \n d, \n i\nFROM \n(\n SELECT \n t.1 AS k, \n t.2 AS v, \n runningDifference(v) AS d, \n runningDifference(cityHash64(t.1)) AS i\n FROM \n (\n SELECT arrayJoin([(\'a\', 1), (\'a\', 2), (\'a\', 3), (\'b\', 11), (\'b\', 13), (\'b\', 15)]) AS t\n )\n)\nWHERE i = 0
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a 1 0 0
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a 2 1 0
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a 3 1 0
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@ -6,8 +6,8 @@ SET enable_optimize_predicate_expression = 1;
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ANALYZE SELECT count() FROM (SELECT a, runningDifference(a) rd FROM ( SELECT * FROM ( SELECT 1 a UNION ALL SELECT 2 a ) ORDER BY a DESC ) WHERE rd=-1 );
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SELECT count() FROM (SELECT a, runningDifference(a) rd FROM ( SELECT * FROM ( SELECT 1 a UNION ALL SELECT 2 a ) ORDER BY a DESC ) WHERE rd=-1 );
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ANALYZE SELECT k, v, d, i FROM (SELECT t.1 AS k, t.2 AS v, runningDifference(v) AS d, runningDifference(xxHash32(t.1)) AS i FROM ( SELECT arrayJoin([('a', 1), ('a', 2), ('a', 3), ('b', 11), ('b', 13), ('b', 15)]) AS t)) WHERE i = 0;
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SELECT k, v, d, i FROM (SELECT t.1 AS k, t.2 AS v, runningDifference(v) AS d, runningDifference(xxHash32(t.1)) AS i FROM ( SELECT arrayJoin([('a', 1), ('a', 2), ('a', 3), ('b', 11), ('b', 13), ('b', 15)]) AS t)) WHERE i = 0;
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ANALYZE SELECT k, v, d, i FROM (SELECT t.1 AS k, t.2 AS v, runningDifference(v) AS d, runningDifference(cityHash64(t.1)) AS i FROM ( SELECT arrayJoin([('a', 1), ('a', 2), ('a', 3), ('b', 11), ('b', 13), ('b', 15)]) AS t)) WHERE i = 0;
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SELECT k, v, d, i FROM (SELECT t.1 AS k, t.2 AS v, runningDifference(v) AS d, runningDifference(cityHash64(t.1)) AS i FROM ( SELECT arrayJoin([('a', 1), ('a', 2), ('a', 3), ('b', 11), ('b', 13), ('b', 15)]) AS t)) WHERE i = 0;
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-- https://github.com/ClickHouse/ClickHouse/issues/5682
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ANALYZE SELECT co,co2,co3,num FROM ( SELECT co,co2,co3,count() AS num FROM ( SELECT 1 AS co,2 AS co2 ,3 AS co3 ) GROUP BY cube (co,co2,co3) ) WHERE co!=0 AND co2 !=2;
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