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Merge pull request #15064 from den-crane/tests/CTE

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more tests for CTE
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alexey-milovidov 2020-09-21 20:41:53 +03:00 committed by GitHub
commit 7744eccd0a
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18
tests/queries/0_stateless/01495_subqueries_in_with_statement.reference
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@ -12,3 +12,21 @@
4 5
4 5
4 5
---------------------------
42
42
0
42
42
42
\N
42
42
42
42
42
45
\N
\N
42
42

60
tests/queries/0_stateless/01495_subqueries_in_with_statement.sql
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@ -11,3 +11,63 @@ SELECT * FROM (WITH test1 AS (SELECT toInt32(*) i FROM numbers(5)) SELECT * FROM
WITH test1 AS (SELECT i + 1, j + 1 FROM test1) SELECT toInt64(4) i, toInt64(5) j FROM numbers(3) WHERE (i, j) IN test1;
DROP TABLE IF EXISTS test1;
select '---------------------------';
set empty_result_for_aggregation_by_empty_set = 0;
WITH test1 AS (SELECT number-1 as n FROM numbers(42))
SELECT max(n+1)+1 z FROM test1;
WITH test1 AS (SELECT number-1 as n FROM numbers(42))
SELECT max(n+1)+1 z FROM test1 join test1 x using n having z - 1 = (select min(n-1)+41 from test1) + 2;
WITH test1 AS (SELECT number-1 as n FROM numbers(4442) order by n limit 100)
SELECT max(n) FROM test1 where n=422;
WITH test1 AS (SELECT number-1 as n FROM numbers(4442) order by n limit 100)
SELECT max(n) FROM test1 where n=42;
drop table if exists with_test ;
create table with_test engine=Memory as select cast(number-1 as Nullable(Int64)) n from numbers(10000);
WITH test1 AS (SELECT n FROM with_test where n <= 40)
SELECT max(n+1)+1 z FROM test1 join test1 x using (n) having max(n+1)+1 - 1 = (select min(n-1)+41 from test1) + 2;
WITH test1 AS (SELECT n FROM with_test where n <= 40)
SELECT max(n+1)+1 z FROM test1 join test1 x using (n) having z - 1 = (select min(n-1)+41 from test1) + 2;
WITH test1 AS (SELECT n FROM with_test order by n limit 100)
SELECT max(n) FROM test1 where n=422;
WITH test1 AS (SELECT n FROM with_test order by n limit 100)
SELECT max(n) FROM test1 where n=42;
WITH test1 AS (SELECT n FROM with_test where n = 42 order by n limit 100)
SELECT max(n) FROM test1 where n=42;
WITH test1 AS (SELECT n FROM with_test where n = 42 or 1=1 order by n limit 100)
SELECT max(n) FROM test1 where n=42;
WITH test1 AS (SELECT n, null as b FROM with_test where n = 42 or b is null order by n limit 100)
SELECT max(n) FROM test1 where n=42;
WITH test1 AS (SELECT n, null b FROM with_test where b is null)
SELECT max(n) FROM test1 where n=42;
WITH test1 AS (SELECT n, null b FROM with_test where b is null or 1=1)
SELECT max(n) FROM test1 where n=45;
WITH test1 AS (SELECT n, null b FROM with_test where b is null and n = 42)
SELECT max(n) FROM test1 where n=45;
WITH test1 AS (SELECT n, null b FROM with_test where 1=1 and n = 42 order by n)
SELECT max(n) FROM test1 where n=45;
WITH test1 AS (SELECT n, null b, n+1 m FROM with_test where 1=0 or n = 42 order by n limit 4)
SELECT max(n) m FROM test1 where test1.m=43 having max(n)=42;
WITH test1 AS (SELECT n, null b, n+1 m FROM with_test where n = 42 order by n limit 4)
SELECT max(n) m FROM test1 where b is null and test1.m=43 having m=42 limit 4;
drop table with_test ;