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Suppress the stderr of running commands by default

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This commit is contained in:
Mikhail f. Shiryaev 2023-01-26 15:19:09 +01:00
parent cc691c30af
commit 975b3a2de8
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GPG Key ID: 4B02ED204C7D93F4
1 changed files with 12 additions and 1 deletions
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13
tests/ci/release.py
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@ -72,11 +72,13 @@ class Release:
release_commit: str,
release_type: Literal["major", "minor", "patch"],
dry_run: bool,
with_stderr: bool,
):
self.repo = repo
self._release_commit = ""
self.release_commit = release_commit
self.dry_run = dry_run
self.with_stderr = with_stderr
assert release_type in self.BIG + self.SMALL
self.release_type = release_type
self._git = Git()
@ -94,6 +96,8 @@ class Release:
if dry_run:
logging.info("Would run command%s:\n %s", cwd_text, cmd)
return ""
if not self.with_stderr:
kwargs["stderr"] = subprocess.DEVNULL
logging.info("Running command%s:\n %s", cwd_text, cmd)
return self._git.run(cmd, cwd, **kwargs)
@ -610,6 +614,11 @@ def parse_args() -> argparse.Namespace:
action="store_true",
help="do not make any actual changes in the repo, just show what will be done",
)
parser.add_argument(
"--with-stderr",
action="store_true",
help="if set, the stderr of all subprocess commands will be printed as well",
)
return parser.parse_args()
@ -618,7 +627,9 @@ def main():
logging.basicConfig(level=logging.INFO)
args = parse_args()
repo = Repo(args.repo, args.remote_protocol)
release = Release(repo, args.commit, args.release_type, args.dry_run)
release = Release(
repo, args.commit, args.release_type, args.dry_run, args.with_stderr
)
release.do(args.check_dirty, args.check_branch)