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ISSUES-3225 fix alias conflict when predicate optimization
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03d85227d1
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@ -222,6 +222,8 @@ void PredicateExpressionsOptimizer::cloneOuterPredicateForInnerPredicate(
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{
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inner_predicate = outer_predicate->clone();
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/// clears the alias name contained in the outer predicate
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cleanExpressionAlias(inner_predicate);
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IdentifiersWithQualifiedNameSet new_expression_requires;
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getDependenciesAndQualifiedOfExpression(inner_predicate, new_expression_requires, tables);
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@ -419,4 +421,14 @@ std::vector<ASTTableExpression *> PredicateExpressionsOptimizer::getSelectTables
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return tables_expression;
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}
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void PredicateExpressionsOptimizer::cleanExpressionAlias(ASTPtr & expression)
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{
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const auto my_alias = expression->tryGetAlias();
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if (!my_alias.empty())
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expression->setAlias("");
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for (auto & child : expression->children)
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cleanExpressionAlias(child);
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}
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}
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@ -88,6 +88,8 @@ private:
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std::vector<ASTTableExpression *> getSelectTablesExpression(ASTSelectQuery * select_query);
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ASTs evaluateAsterisk(ASTSelectQuery * select_query, const ASTPtr & asterisk);
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void cleanExpressionAlias(ASTPtr & expression);
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};
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}
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@ -6,6 +6,7 @@
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1
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1
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1
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1
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1 1
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3 3
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3 3
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@ -17,6 +17,7 @@ SELECT 1 AS id WHERE id = 1;
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SELECT arrayJoin([1,2,3]) AS id WHERE id = 1;
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SELECT '-------Need push down-------';
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SELECT toString(value) AS value FROM (SELECT 1 AS value) WHERE value = '1';
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SELECT * FROM (SELECT 1 AS id UNION ALL SELECT 2) WHERE id = 1;
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SELECT * FROM (SELECT arrayJoin([1, 2, 3]) AS id) WHERE id = 1;
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SELECT id FROM (SELECT arrayJoin([1, 2, 3]) AS id) WHERE id = 1;
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