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fix style + add docs

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21
docs/en/sql-reference/data-types/special-data-types/interval.md
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@ -53,29 +53,28 @@ SELECT now() as current_date_time, current_date_time + INTERVAL 4 DAY
└─────────────────────┴───────────────────────────────┘
```
Intervals with different types can’t be combined. You can’t use intervals like `4 DAY 1 HOUR`. Specify intervals in units that are smaller or equal to the smallest unit of the interval, for example, the interval `1 day and an hour` interval can be expressed as `25 HOUR` or `90000 SECOND`.
You can’t perform arithmetical operations with `Interval`-type values, but you can add intervals of different types consequently to values in `Date` or `DateTime` data types. For example:
Also it is possible to use multiple intervals simultaneously:
``` sql
SELECT now() AS current_date_time, current_date_time + INTERVAL 4 DAY + INTERVAL 3 HOUR
SELECT now() AS current_date_time, current_date_time + (INTERVAL 4 DAY + INTERVAL 3 HOUR)
```
``` text
┌───current_date_time─┬─plus(plus(now(), toIntervalDay(4)), toIntervalHour(3))─┐
│ 2019-10-23 11:16:28 │ 2019-10-27 14:16:28 │
└─────────────────────┴────────────────────────────────────────────────────────┘
┌───current_date_time─┬─plus(current_date_time, plus(toIntervalDay(4), toIntervalHour(3)))─┐
│ 2024-08-08 18:31:39 │ 2024-08-12 21:31:39 │
└─────────────────────┴────────────────────────────────────────────────────────────────────┘
```
The following query causes an exception:
And to compare values with different intevals:
``` sql
select now() AS current_date_time, current_date_time + (INTERVAL 4 DAY + INTERVAL 3 HOUR)
SELECT toIntervalMicrosecond(3600000000) = toIntervalHour(1);
```
``` text
Received exception from server (version 19.14.1):
Code: 43. DB::Exception: Received from localhost:9000. DB::Exception: Wrong argument types for function plus: if one argument is Interval, then another must be Date or DateTime..
┌─less(toIntervalMicrosecond(179999999), toIntervalMinute(3))─┐
│ 1 │
└─────────────────────────────────────────────────────────────┘
```
## See Also

21
docs/ru/sql-reference/data-types/special-data-types/interval.md
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@ -54,29 +54,28 @@ SELECT now() as current_date_time, current_date_time + INTERVAL 4 DAY
└─────────────────────┴───────────────────────────────┘
```
Нельзя объединять интервалы различных типов. Нельзя использовать интервалы вида `4 DAY 1 HOUR`. Вместо этого выражайте интервал в единицах меньших или равных минимальной единице интервала, например, интервал «1 день и 1 час» можно выразить как `25 HOUR` или `90000 SECOND`.
Арифметические операции со значениями типов `Interval` не доступны, однако можно последовательно добавлять различные интервалы к значениям типов `Date` и `DateTime`. Например:
Также можно использовать различные типы интервалов одновременно:
``` sql
SELECT now() AS current_date_time, current_date_time + INTERVAL 4 DAY + INTERVAL 3 HOUR
SELECT now() AS current_date_time, current_date_time + (INTERVAL 4 DAY + INTERVAL 3 HOUR)
```
``` text
┌───current_date_time─┬─plus(plus(now(), toIntervalDay(4)), toIntervalHour(3))─┐
│ 2019-10-23 11:16:28 │ 2019-10-27 14:16:28 │
└─────────────────────┴────────────────────────────────────────────────────────┘
┌───current_date_time─┬─plus(current_date_time, plus(toIntervalDay(4), toIntervalHour(3)))─┐
│ 2024-08-08 18:31:39 │ 2024-08-12 21:31:39 │
└─────────────────────┴────────────────────────────────────────────────────────────────────┘
```
Следующий запрос приведёт к генерированию исключения:
И сравнивать значения из разными интервалами:
``` sql
select now() AS current_date_time, current_date_time + (INTERVAL 4 DAY + INTERVAL 3 HOUR)
SELECT toIntervalMicrosecond(3600000000) = toIntervalHour(1);
```
``` text
Received exception from server (version 19.14.1):
Code: 43. DB::Exception: Received from localhost:9000. DB::Exception: Wrong argument types for function plus: if one argument is Interval, then another must be Date or DateTime..
┌─less(toIntervalMicrosecond(179999999), toIntervalMinute(3))─┐
│ 1 │
└─────────────────────────────────────────────────────────────┘
```
## Смотрите также {#smotrite-takzhe}

21
docs/zh/sql-reference/data-types/special-data-types/interval.md
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@ -55,29 +55,28 @@ SELECT now() as current_date_time, current_date_time + INTERVAL 4 DAY
└─────────────────────┴───────────────────────────────┘
```
不同类型的间隔不能合并。 你不能使用诸如 `4 DAY 1 HOUR` 的时间间隔. 以小于或等于时间间隔最小单位的单位来指定间隔，例如，时间间隔 `1 day and an hour` 可以表示为 `25 HOUR` 或 `90000 SECOND`.
你不能对 `Interval` 类型的值执行算术运算，但你可以向 `Date` 或 `DateTime` 数据类型的值添加不同类型的时间间隔，例如:
也可以同時使用多個間隔：
``` sql
SELECT now() AS current_date_time, current_date_time + INTERVAL 4 DAY + INTERVAL 3 HOUR
SELECT now() AS current_date_time, current_date_time + (INTERVAL 4 DAY + INTERVAL 3 HOUR)
```
``` text
┌───current_date_time─┬─plus(plus(now(), toIntervalDay(4)), toIntervalHour(3))─┐
│ 2019-10-23 11:16:28 │ 2019-10-27 14:16:28 │
└─────────────────────┴────────────────────────────────────────────────────────┘
┌───current_date_time─┬─plus(current_date_time, plus(toIntervalDay(4), toIntervalHour(3)))─┐
│ 2024-08-08 18:31:39 │ 2024-08-12 21:31:39 │
└─────────────────────┴────────────────────────────────────────────────────────────────────┘
```
以下查询将导致异常:
並比較不同直數的值：
``` sql
select now() AS current_date_time, current_date_time + (INTERVAL 4 DAY + INTERVAL 3 HOUR)
SELECT toIntervalMicrosecond(3600000000) = toIntervalHour(1);
```
``` text
Received exception from server (version 19.14.1):
Code: 43. DB::Exception: Received from localhost:9000. DB::Exception: Wrong argument types for function plus: if one argument is Interval, then another must be Date or DateTime..
┌─less(toIntervalMicrosecond(179999999), toIntervalMinute(3))─┐
│ 1 │
└─────────────────────────────────────────────────────────────┘
```
## 另请参阅 {#see-also}

2
src/DataTypes/getLeastSupertype.cpp
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@ -252,7 +252,7 @@ DataTypePtr findSmallestIntervalSuperType(const DataTypes &types, TypeIndexSet &
}
if (is_higher_interval && min_granularity <= 8)
throw Exception(ErrorCodes::ILLEGAL_TYPE_OF_ARGUMENT, "Cannot compare intervals {} and {} because the amount of days in month is not determined", types[0]->getName(), types[1]->getName());
throw Exception(ErrorCodes::NO_COMMON_TYPE, "Cannot compare intervals {} and {} because the amount of days in month is not determined", types[0]->getName(), types[1]->getName());
if (smallest_type)
{