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Don't replace tables with compound names

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This commit is contained in:
Ivan Lezhankin 2019-02-26 20:22:05 +03:00
parent 7f130d2362
commit e9849ba8de
2 changed files with 4 additions and 3 deletions
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5
dbms/src/Interpreters/SyntaxAnalyzer.cpp
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@ -605,11 +605,12 @@ void replaceJoinedTable(const ASTTablesInSelectQueryElement* join)
if (table_expr.database_and_table_name) if (table_expr.database_and_table_name)
{ {
auto & table_id = typeid_cast<ASTIdentifier &>(*table_expr.database_and_table_name.get()); auto & table_id = typeid_cast<ASTIdentifier &>(*table_expr.database_and_table_name.get());
String expr = "(select * from " + table_id.name + ")"; String expr = "(select * from " + table_id.name + ") as " + table_id.shortName();
// FIXME: since the expression "a as b" exposes both "a" and "b" names, which is not equivalent to "(select * from a) as b", // FIXME: since the expression "a as b" exposes both "a" and "b" names, which is not equivalent to "(select * from a) as b",
// we can't replace aliased tables. // we can't replace aliased tables.
if (table_id.alias.empty()) // FIXME: long table names include database name, which we can't save within alias.
if (table_id.alias.empty() && table_id.isShort())
{ {
ParserTableExpression parser; ParserTableExpression parser;
table_expr = static_cast<ASTTableExpression &>(*parseQuery(parser, expr, 0)); table_expr = static_cast<ASTTableExpression &>(*parseQuery(parser, expr, 0));

2
dbms/tests/queries/0_stateless/00597_push_down_predicate.reference
View File

@ -43,7 +43,7 @@ SELECT \n date, \n id, \n name, \n value\nFROM \n(\n SELECT \n
2000-01-01 1 test string 1 1 2000-01-01 1 test string 1 1
SELECT \n date, \n id, \n name, \n value, \n date, \n name, \n value\nFROM \n(\n SELECT \n date, \n id, \n name, \n value\n FROM test.test \n WHERE id = 1\n) \nANY LEFT JOIN \n(\n SELECT *\n FROM test.test \n WHERE id = 1\n) USING (id)\nWHERE id = 1 SELECT \n date, \n id, \n name, \n value, \n date, \n name, \n value\nFROM \n(\n SELECT \n date, \n id, \n name, \n value\n FROM test.test \n WHERE id = 1\n) \nANY LEFT JOIN \n(\n SELECT *\n FROM test.test \n WHERE id = 1\n) USING (id)\nWHERE id = 1
2000-01-01 1 test string 1 1 2000-01-01 test string 1 1 2000-01-01 1 test string 1 1 2000-01-01 test string 1 1
SELECT \n id, \n date, \n name, \n value\nFROM \n(\n SELECT toInt8(1) AS id\n) \nANY LEFT JOIN \n(\n SELECT *\n FROM test.test \n WHERE value = 1\n) USING (id)\nWHERE value = 1 SELECT \n id, \n date, \n name, \n value\nFROM \n(\n SELECT toInt8(1) AS id\n) \nANY LEFT JOIN \n(\n SELECT *\n FROM test.test \n WHERE value = 1\n) AS test USING (id)\nWHERE value = 1
1 2000-01-01 test string 1 1 1 2000-01-01 test string 1 1
SELECT b.value\nFROM \n(\n SELECT toInt8(1) AS id\n) \nANY LEFT JOIN test.test AS b USING (id)\nWHERE value = 1 SELECT b.value\nFROM \n(\n SELECT toInt8(1) AS id\n) \nANY LEFT JOIN test.test AS b USING (id)\nWHERE value = 1
1 1