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16 lines
542 B
SQL
16 lines
542 B
SQL
-- Test that the string hash map works properly with keys containing zero
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-- bytes.
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-- Keys with no central '1' are mostly duplicates. The unique keys
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-- in this group are '', '\0', ...., '\0 x 34', to a total of 35. All other
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-- keys are unique.
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select count(*) = 18 * 18 * 17 + 35
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from (
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select key
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from (
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with 18 as n
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select repeat('\0', number % n)
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|| repeat('1', intDiv(number, n) % n)
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|| repeat('\0', intDiv(number, n * n) % n) key
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from numbers(18 * 18 * 18))
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group by key);
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