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126 lines
4.0 KiB
C++
126 lines
4.0 KiB
C++
#include "consistent_hashing.h"
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#include "bitops.h"
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#include "popcount.h"
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#include <stdexcept>
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/*
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* (all numbers are written in big-endian manner: the least significant digit on the right)
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* (only bit representations are used - no hex or octal, leading zeroes are ommited)
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*
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* Consistent hashing scheme:
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*
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* (sizeof(TValue) * 8, y] (y, 0]
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* a = * ablock
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* b = * cblock
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*
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* (sizeof(TValue) * 8, k] (k, 0]
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* c = * cblock
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*
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* d = *
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*
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* k - is determined by 2^(k-1) < n <= 2^k inequality
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* z - is number of ones in cblock
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* y - number of digits after first one in cblock
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*
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* The cblock determines logic of using a- and b- blocks:
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*
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* bits of cblock | result of a function
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* 0 : 0
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* 1 : 1 (optimization, the next case includes this one)
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* 1?..? : 1ablock (z is even) or 1bblock (z is odd) if possible (<n)
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*
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* If last case is not possible (>=n), than smooth moving from n=2^(k-1) to n=2^k is applied.
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* Using "*" bits of a-,b-,c-,d- blocks uint64_t value is combined, modulo of which determines
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* if the value should be greather than 2^(k-1) or ConsistentHashing(x, 2^(k-1)) should be used.
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* The last case is optimized according to previous checks.
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*/
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namespace {
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template<class TValue>
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TValue PowerOf2(size_t k) {
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return (TValue)0x1 << k;
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}
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template<class TValue>
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TValue SelectAOrBBlock(TValue a, TValue b, TValue cBlock) {
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size_t z = PopCount<uint64_t>(cBlock);
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bool useABlock = z % 2 == 0;
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return useABlock ? a : b;
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}
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// Gets the exact result for n = k2 = 2 ^ k
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template<class TValue>
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size_t ConsistentHashingForPowersOf2(TValue a, TValue b, TValue c, TValue k2) {
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TValue cBlock = c & (k2 - 1); // (k, 0] bits of c
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// Zero and one cases
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if (cBlock < 2) {
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// First two cases of result function table: 0 if cblock is 0, 1 if cblock is 1.
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return cBlock;
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}
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size_t y = GetValueBitCount<uint64_t>(cBlock) - 1; // cblock = 0..01?..? (y = number of digits after 1), y > 0
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TValue y2 = PowerOf2<TValue>(y); // y2 = 2^y
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TValue abBlock = SelectAOrBBlock(a, b, cBlock) & (y2 - 1);
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return y2 + abBlock;
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}
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template<class TValue>
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uint64_t GetAsteriskBits(TValue a, TValue b, TValue c, TValue d, size_t k) {
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size_t shift = sizeof(TValue) * 8 - k;
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uint64_t res = (d << shift) | (c >> k);
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++shift;
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res <<= shift;
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res |= b >> (k - 1);
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res <<= shift;
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res |= a >> (k - 1);
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return res;
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}
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template<class TValue>
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size_t ConsistentHashingImpl(TValue a, TValue b, TValue c, TValue d, size_t n) {
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if (n <= 0)
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throw std::runtime_error("Can't map consistently to a zero values.");
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// Uninteresting case
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if (n == 1) {
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return 0;
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}
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size_t k = GetValueBitCount(n - 1); // 2^(k-1) < n <= 2^k, k >= 1
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TValue k2 = PowerOf2<TValue>(k); // k2 = 2^k
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size_t largeValue;
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{
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// Bit determined variant. Large scheme.
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largeValue = ConsistentHashingForPowersOf2(a, b, c, k2);
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if (largeValue < n) {
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return largeValue;
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}
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}
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// Since largeValue is not assigned yet
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// Smooth moving from one bit scheme to another
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TValue k21 = PowerOf2<TValue>(k - 1);
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{
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size_t s = GetAsteriskBits(a, b, c, d, k) % (largeValue * (largeValue + 1));
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size_t largeValue2 = s / k2 + k21;
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if (largeValue2 < n) {
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return largeValue2;
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}
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}
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// Bit determined variant. Short scheme.
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return ConsistentHashingForPowersOf2(a, b, c, k21); // Do not apply checks. It is always less than k21 = 2^(k-1)
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}
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} // namespace // anonymous
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std::size_t ConsistentHashing(std::uint64_t x, std::size_t n) {
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uint32_t lo = LO_32(x);
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uint32_t hi = HI_32(x);
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return ConsistentHashingImpl<uint16_t>(LO_16(lo), HI_16(lo), LO_16(hi), HI_16(hi), n);
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}
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std::size_t ConsistentHashing(std::uint64_t lo, std::uint64_t hi, std::size_t n) {
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return ConsistentHashingImpl<uint32_t>(LO_32(lo), HI_32(lo), LO_32(hi), HI_32(hi), n);
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}
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