ClickHouse/tests/queries/0_stateless/01591_window_functions.reference

-- { echo }

set allow_experimental_window_functions = 1;
-- just something basic
select number, count() over (partition by intDiv(number, 3) order by number) from numbers(10);
0	1
1	2
2	3
3	1
4	2
5	3
6	1
7	2
8	3
9	1
-- proper calculation across blocks
select number, max(number) over (partition by intDiv(number, 3) order by number desc) from numbers(10) settings max_block_size = 2;
2	2
1	2
0	2
5	5
4	5
3	5
8	8
7	8
6	8
9	9
-- not a window function
select number, abs(number) over (partition by toString(intDiv(number, 3))) from numbers(10); -- { serverError 63 }
-- no partition by
select number, avg(number) over (order by number) from numbers(10);
0	0
1	0.5
2	1
3	1.5
4	2
5	2.5
6	3
7	3.5
8	4
9	4.5
-- no order by
select number, quantileExact(number) over (partition by intDiv(number, 3)) from numbers(10);
0	0
1	1
2	1
3	3
4	4
5	4
6	6
7	7
8	7
9	9
-- can add an alias after window spec
select number, quantileExact(number) over (partition by intDiv(number, 3)) q from numbers(10);
0	0
1	1
2	1
3	3
4	4
5	4
6	6
7	7
8	7
9	9
-- can't reference it yet -- the window functions are calculated at the
-- last stage of select, after all other functions.
select q * 10, quantileExact(number) over (partition by intDiv(number, 3)) q from numbers(10); -- { serverError 47 }
-- must work in WHERE if you wrap it in a subquery
select * from (select count(*) over () c from numbers(3)) where c > 0;
1
2
3
-- should work in ORDER BY
select number, max(number) over (partition by intDiv(number, 3) order by number desc) m from numbers(10) order by m desc, number;
9	9
6	8
7	8
8	8
3	5
4	5
5	5
0	2
1	2
2	2
-- also works in ORDER BY if you wrap it in a subquery
select * from (select count(*) over () c from numbers(3)) order by c;
1
2
3
-- Example with window function only in ORDER BY. Here we make a rank of all
-- numbers sorted descending, and then sort by this rank descending, and must get
-- the ascending order.
select * from (select * from numbers(5) order by rand()) order by count() over (order by number desc) desc;
0
1
2
3
4
-- Aggregate functions as window function arguments. This query is semantically
-- the same as the above one, only we replace `number` with
-- `any(number) group by number` and so on.
select * from (select * from numbers(5) order by rand()) group by number order by sum(any(number + 1)) over (order by min(number) desc) desc;
0
1
2
3
4
-- some more simple cases w/aggregate functions
select sum(any(number)) over () from numbers(1);
0
select sum(any(number) + 1) over () from numbers(1);
1
select sum(any(number + 1)) over () from numbers(1);
1
-- different windows
-- an explain test would also be helpful, but it's too immature now and I don't
-- want to change reference all the time
select number, max(number) over (partition by intDiv(number, 3) order by number desc), count(number) over (partition by intDiv(number, 5) order by number) as m from numbers(31) order by number settings max_block_size = 2;
0	2	1
1	2	2
2	2	3
3	5	4
4	5	5
5	5	1
6	8	2
7	8	3
8	8	4
9	11	5
10	11	1
11	11	2
12	14	3
13	14	4
14	14	5
15	17	1
16	17	2
17	17	3
18	20	4
19	20	5
20	20	1
21	23	2
22	23	3
23	23	4
24	26	5
25	26	1
26	26	2
27	29	3
28	29	4
29	29	5
30	30	1
-- two functions over the same window
-- an explain test would also be helpful, but it's too immature now and I don't
-- want to change reference all the time
select number, max(number) over (partition by intDiv(number, 3) order by number desc), count(number) over (partition by intDiv(number, 3) order by number desc) as m from numbers(7) order by number settings max_block_size = 2;
0	2	3
1	2	2
2	2	1
3	5	3
4	5	2
5	5	1
6	6	1
-- check that we can work with constant columns
select median(x) over (partition by x) from (select 1 x);
1
-- an empty window definition is valid as well
select groupArray(number) over () from numbers(3);
[0]
[0,1]
[0,1,2]
-- This one tests we properly process the window  function arguments.
-- Seen errors like 'column `1` not found' from count(1).
select count(1) over (), max(number + 1) over () from numbers(3);
1	3
-- Should work in DISTINCT
select distinct sum(0) over () from numbers(2);
0
select distinct any(number) over () from numbers(2);
0
-- Various kinds of aliases are properly substituted into various parts of window
-- function definition.
with number + 1 as x select intDiv(number, 3) as y, sum(x + y) over (partition by y order by x) from numbers(7);
0	1
0	3
0	6
1	5
1	11
1	18
2	9
-- WINDOW clause
select 1 window w1 as ();
1
select sum(number) over w1, sum(number) over w2
from numbers(10)
window
    w1 as (),
    w2 as (partition by intDiv(number, 3))
;
0	0
1	1
3	3
6	3
10	7
15	12
21	6
28	13
36	21
45	9
select
    sum(number) over w1,
    sum(number) over (partition by intDiv(number, 3))
from numbers(10)
window
    w1 as (partition by intDiv(number, 3))
;
0	0
1	1
3	3
3	3
7	7
12	12
6	6
13	13
21	21
9	9