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36 lines
2.1 KiB
SQL
36 lines
2.1 KiB
SQL
DROP TABLE IF EXISTS group_by_all;
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CREATE TABLE group_by_all
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(
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a String,
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b int,
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c int
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)
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engine = Memory;
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insert into group_by_all values ('abc1', 1, 1), ('abc2', 1, 1), ('abc3', 1, 1), ('abc4', 1, 1);
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select a, count(b) from group_by_all group by all order by a;
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select substring(a, 1, 3), count(b) from group_by_all group by all;
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select substring(a, 1, 3), substring(substring(a, 1, 2), 1, count(b)) from group_by_all group by all;
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select substring(a, 1, 3), substring(substring(a, 1, 2), c, count(b)) from group_by_all group by all;
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select substring(a, 1, 3), substring(substring(a, c, 2), c, count(b)) from group_by_all group by all;
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select substring(a, 1, 3), substring(substring(a, c + 1, 2), 1, count(b)) from group_by_all group by all;
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select substring(a, 1, 3), substring(substring(a, c + 1, 2), c, count(b)) from group_by_all group by all;
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select substring(a, 1, 3), substring(substring(substring(a, c, count(b)), 1, count(b)), 1, count(b)) from group_by_all group by all;
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select substring(a, 1, 3), substring(a, 1, count(b)) from group_by_all group by all;
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select count(b) AS len, substring(a, 1, 3), substring(a, 1, len) from group_by_all group by all;
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SET enable_analyzer = 1;
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select a, count(b) from group_by_all group by all order by a;
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select substring(a, 1, 3), count(b) from group_by_all group by all;
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select substring(a, 1, 3), substring(substring(a, 1, 2), 1, count(b)) from group_by_all group by all;
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select substring(a, 1, 3), substring(substring(a, 1, 2), c, count(b)) from group_by_all group by all;
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select substring(a, 1, 3), substring(substring(a, c, 2), c, count(b)) from group_by_all group by all;
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select substring(a, 1, 3), substring(substring(a, c + 1, 2), 1, count(b)) from group_by_all group by all;
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select substring(a, 1, 3), substring(substring(a, c + 1, 2), c, count(b)) from group_by_all group by all;
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select substring(a, 1, 3), substring(substring(substring(a, c, count(b)), 1, count(b)), 1, count(b)) from group_by_all group by all;
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select substring(a, 1, 3), substring(a, 1, count(b)) from group_by_all group by all;
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select count(b) AS len, substring(a, 1, 3), substring(a, 1, len) from group_by_all group by all;
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