3.7 KiB
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61 | arrayJoin |
arrayJoin function
This is a very unusual function.
Normal functions do not change a set of rows, but just change the values in each row (map).
Aggregate functions compress a set of rows (fold or reduce).
The arrayJoin
function takes each row and generates a set of rows (unfold).
This function takes an array as an argument, and propagates the source row to multiple rows for the number of elements in the array. All the values in columns are simply copied, except the values in the column where this function is applied; it is replaced with the corresponding array value.
Example:
SELECT arrayJoin([1, 2, 3] AS src) AS dst, 'Hello', src
┌─dst─┬─\'Hello\'─┬─src─────┐
│ 1 │ Hello │ [1,2,3] │
│ 2 │ Hello │ [1,2,3] │
│ 3 │ Hello │ [1,2,3] │
└─────┴───────────┴─────────┘
The arrayJoin
function affects all sections of the query, including the WHERE
section. Notice the result 2, even though the subquery returned 1 row.
Example:
SELECT sum(1) AS impressions
FROM
(
SELECT ['Istanbul', 'Berlin', 'Bobruisk'] AS cities
)
WHERE arrayJoin(cities) IN ['Istanbul', 'Berlin'];
┌─impressions─┐
│ 2 │
└─────────────┘
A query can use multiple arrayJoin
functions. In this case, the transformation is performed multiple times and the rows are multiplied.
Example:
SELECT
sum(1) AS impressions,
arrayJoin(cities) AS city,
arrayJoin(browsers) AS browser
FROM
(
SELECT
['Istanbul', 'Berlin', 'Bobruisk'] AS cities,
['Firefox', 'Chrome', 'Chrome'] AS browsers
)
GROUP BY
2,
3
┌─impressions─┬─city─────┬─browser─┐
│ 2 │ Istanbul │ Chrome │
│ 1 │ Istanbul │ Firefox │
│ 2 │ Berlin │ Chrome │
│ 1 │ Berlin │ Firefox │
│ 2 │ Bobruisk │ Chrome │
│ 1 │ Bobruisk │ Firefox │
└─────────────┴──────────┴─────────┘
Note the ARRAY JOIN syntax in the SELECT query, which provides broader possibilities.
ARRAY JOIN
allows you to convert multiple arrays with the same number of elements at a time.
Example:
SELECT
sum(1) AS impressions,
city,
browser
FROM
(
SELECT
['Istanbul', 'Berlin', 'Bobruisk'] AS cities,
['Firefox', 'Chrome', 'Chrome'] AS browsers
)
ARRAY JOIN
cities AS city,
browsers AS browser
GROUP BY
2,
3
┌─impressions─┬─city─────┬─browser─┐
│ 1 │ Istanbul │ Firefox │
│ 1 │ Berlin │ Chrome │
│ 1 │ Bobruisk │ Chrome │
└─────────────┴──────────┴─────────┘
Or you can use Tuple
Example:
SELECT
sum(1) AS impressions,
(arrayJoin(arrayZip(cities, browsers)) AS t).1 AS city,
t.2 AS browser
FROM
(
SELECT
['Istanbul', 'Berlin', 'Bobruisk'] AS cities,
['Firefox', 'Chrome', 'Chrome'] AS browsers
)
GROUP BY
2,
3
┌─impressions─┬─city─────┬─browser─┐
│ 1 │ Istanbul │ Firefox │
│ 1 │ Berlin │ Chrome │
│ 1 │ Bobruisk │ Chrome │
└─────────────┴──────────┴─────────┘